7^(2x-5)/3^(8-5x)=5^(3-2x)*11^(3-x)

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Solution for 7^(2x-5)/3^(8-5x)=5^(3-2x)*11^(3-x) equation: 



7^(2x-5)/3^(8-5x)=5^(3-2x)*11^(3-x)

We move all terms to the left:

7^(2x-5)/3^(8-5x)-(5^(3-2x)*11^(3-x))=0



Domain of the equation: 3^(8-5x)!=0

x∈R



We add all the numbers together, and all the variables

7^(2x-5)/3^(-5x+8)-(5^(-2x+3)*11^(-1x+3))=0

We multiply all the terms by the denominator


7^(2x-5)-((5^(-2x+3)*11^(-1x+3)))*3^(-5x+8)=0



We calculate terms in parentheses: -((5^(-2x+3)*11^(-1x+3)))*3^(-5x+8), so:

(5^(-2x+3)*11^(-1x+3)))*3^(-5x+8

We add all the numbers together, and all the variables

-5x+(5^(-2x+3)*11^(-1x+3)))*3^(+8

Back to the equation:

-(-5x+(5^(-2x+3)*11^(-1x+3)))*3^(+8)



We add all the numbers together, and all the variables

7^(2x-5)-(-5x+(5^(-2x+3)*11^(-1x+3)))*3^8=0

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